2b9aa62d69
- we now only the store the lexical form when it's non-canonical - Literal validation and canonicalization - a general RDF.Datatype.Test.Case - also tested datatype implementations for booleans, integers, string and langStrings - use literal sigils in Inspect implementation of Literals when possible
42 lines
1.2 KiB
Elixir
42 lines
1.2 KiB
Elixir
defmodule RDF.IntegerTest do
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use RDF.Datatype.Test.Case, datatype: RDF.Integer, id: RDF.NS.XSD.integer,
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valid: %{
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# input => { value , lexical , canonicalized }
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0 => { 0 , nil , "0" },
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1 => { 1 , nil , "1" },
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"0" => { 0 , nil , "0" },
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"1" => { 1 , nil , "1" },
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"01" => { 1 , "01" , "1" },
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"0123" => { 123 , "0123" , "123" },
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+1 => { 1 , nil , "1" },
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-1 => { -1 , nil , "-1" },
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"+1" => { 1 , "+1" , "1" },
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"-1" => { -1 , nil , "-1" },
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},
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invalid: ~w(foo 10.1 12xyz) ++ [true, false, 3.14, "1 2", "foo 1", "1 foo"]
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describe "equality" do
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test "two literals are equal when they have the same datatype and lexical form" do
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[
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{"1" , 1},
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{"-42" , -42},
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]
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|> Enum.each(fn {l, r} ->
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assert Integer.new(l) == Integer.new(r)
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end)
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end
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test "two literals with same value but different lexical form are not equal" do
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[
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{"01" , 1},
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{"+42" , 42},
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]
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|> Enum.each(fn {l, r} ->
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assert Integer.new(l) != Integer.new(r)
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end)
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end
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end
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end
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